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A metal tool is sharpened by being held against the rim of a wheel on a grinding machine by a force of 185 N?
A metal tool is sharpened by being held against the rim of a wheel on a grinding machine by a force of 185 N. The frictional forces between the rim and the tool grind off small pieces of the tool. The wheel has a radius of 20.0 cm and rotates at 2.60 rev/s. The coefficient of kinetic friction between the wheel and the tool is 0.320. At what rate is energy being transferred from the motor driving the wheel to the thermal energy of the wheel and tool and to the kinetic energy of the material thrown from the tool?
_____W
First find the frictional force F this is 185*0.32 = 59.2N
Then find the tangential speed of the periphery of the wheel - this is 2*pi*0.2*2.6 = 3.267m/s
Then multiply force * speed = 193.4W
The last sentence of your question is unclear. 193.4W is the power required to drive the wheel against the tool for the grinding process; this power will be used for the processes you mention, and also to provide the power required to break up the metal of the tool and the grit of the wheel into small particles, which requires the expenditure of energy. The power delivered by the motor will be larger than 193.4W because of friction in the bearings of the machine, and inefficiency in any gearbox, belt system, etc. We do not have any information from which an estimate of this extra power can be formed.
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